The odds of losing any individual game are 50%. The odds of losing two games in a row are (50%)*(50%) = 25%. The odds of losing nine games in a row is 50% times 50% repeated nine times. This gives odds of 1 in 512. Wow! If they lose heir tenth game in a row, the odds become 1 in 1056. Yikes!

Before we get too carried away with these numbers, let's me make it clear that the odds of losing a game are NOT 50% as teams have different skill levels based on players, injuries, home/away, day/night, etc. Really bad teams have a greater than 50% chance of losing a game, and therefore the odds of losing nine in a row wouldn't be nearly as high. Really good teams have a lesser than 50% of losing a game, and therefore the odds of losing nine in a row would be much higher, although at this point, can one call a team really good if they lose nine in a row?

The other thing to understand is that, if everything is equal, the odds of any nine game stretch are 1 in 512. A team could go WLWLLLWWW and the odds are 1 in 512. A team could go LWLWWLWWW and the odds are also 1 in 512. Thus the odds of 1 in 512 mean very little in baseball. In other words, there are 512 nine came W/L combinations. The odds of every team after nine games having the record (and correct W/L order) they do is 1 in 512.

What's the point of this post then. Well, I'm just trying to put some sort of positive spin on the Twins losing their first nine games (and hopefully no more)!

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